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A bat can detect small objects, such as an insect, whose size is approximately equal to one wavelength of the sound the bat makes. If bats emit a chirp at a frequency of $60.0 \times 10^{3} \mathrm{Hz}$

and the speed of sound in air is $343 \mathrm{m} / \mathrm{s},$ what is the smallest insect a bat can detect?

5.7$\mathrm { mm }$

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So here the frequency is Equalling 60 kilohertz or we can say 6.0 times 10 to the fourth hurts and the speed of sound V is equaling 340 meters per second. So we can say then that the smallest insect that the bat can detect would be equal to the wavelength of the sounds that they are admitting for echo location. So we have then size of the object equaling wavelength, Equalling the velocity over the frequency. So this is 340 meters per second, divided by 6.0 times 10. So the fourth hurts and this is giving us 5.67 times 10 to the negative third meters. So the smallest insect that a bat can detect is a 5.67 millimeter insect. That is the end of the solution. Thank you for watching

Carnegie Mellon University