Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

A batter hits a fly ball which leaves the bat 0.90 $\mathrm{m}$ above theground at an angle of $61^{\circ}$ with an initial speed of 28 $\mathrm{m} / \mathrm{s}$ head-ing toward centerficld. Ignore air resistance. (a) How far fromhome plate would the ball land if not caught? (b) The ball iscaught by the centerficlder who, starting at a distance of 105 $\mathrm{m}$ from home plate, runs straight toward home plate at a constantspeed and makes the catch at ground level. Find his spced.

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

a) $68 \mathrm{m}$b) $7.3 \mathrm{m} / \mathrm{s}$

Physics 101 Mechanics

Chapter 3

Kinematics in Two or Three Dimensions; Vectors

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

Rotation of Rigid Bodies

Dynamics of Rotational Motion

Equilibrium and Elasticity

Rutgers, The State University of New Jersey

Hope College

University of Sheffield

University of Winnipeg

Lectures

02:34

In physics, a rigid body is an object that is not deformed by the stress of external forces. The term "rigid body" is used in the context of classical mechanics, where it refers to a body that has no degrees of freedom and is completely described by its position and the forces applied to it. A rigid body is a special case of a solid body, and is one type of spatial body. The term "rigid body" is also used in the context of continuum mechanics, where it refers to a solid body that is deformed by external forces, but does not change in volume. In continuum mechanics, a rigid body is a continuous body that has no internal degrees of freedom. The term "rigid body" is also used in the context of quantum mechanics, where it refers to a body that cannot be squeezed into a smaller volume without changing its shape.

02:21

In physics, rotational dynamics is the study of the kinematics and kinetics of rotational motion, the motion of rigid bodies, and the about axes of the body. It can be divided into the study of torque and the study of angular velocity.

04:36

A batter hits a fly ball w…

03:48

05:24

08:09

02:36

03:10

08:29

At $t=0$ a batter hits a b…

08:41

A home run is hit in such …

07:16

04:28

A ballplayer standing at h…

04:00

02:45

A batter hits a baseball a…

05:31

A World Series batter hits…

04:06

A baseball player hits a h…

Our question says that a batter had to fly ball, which leaves the bat at 0.9 meters above the ground at an angle of 61 degrees with an initial velocity of 28 meters per second headed towards center field. Ignore air resistance. A how far from home plate with the ball land if it was not caught, and b the ball is caught by the centerfielder, who starts at a distance of 105 meters from home plate runs straight towards home plate at a constant speed. It makes the catch a ground level. What is his speed in order for him to be able to do this? So I wrote down here what? We're given V. Nona's 28 meters per second Fada, 61 degrees. The height of the ball hit off the bat a 0.9 meters. That's why not and for the first instance well, and even in the last one we consider to be a ground level and ground level zero, so are final value. Why zero? So the first thing we need to do to find out how far it goes if we know its initial velocity and its initial angle. We know V of X, so to find X when you know the time it travels. Okay, so the time it travels can be found by using. Why? Because people too. Why not? Plus the of wind of lost in the white direction times the time plus 1/2 acceleration in the wind direction times the Times Square. Okay, well, let's go ahead and simplify this. We know that. Why is zero So this is zero is equal to Why not? Plus be of why times the time minus 1/2 G. Because the acceleration in my direction is gravity In the minus y directions. This is minus 1/2 G comes the time squared. So if you want to solve for time we can use the quadratic formula. Pretty is going to be equal to, uh, minus v not signed. Data plus or minus the square root of Vina signed data in that square. So, Veena science data, Let's make this look more like a data area squared, Uh, minus four times minus 1/2 G multiplied by Why not? Okay. Oh, divided by two times minus 1/2 Chief. Okay, so now we have we know all the values that we need to plug in in this equation we have. Why not? 0.9 meters fada, 61 degrees V nonce, 28 meters per second. Gravity is 9.8 meters per second squared. So plug all those values in on your calculator and you'll find that you're gonna get two values for tea because the plus or minus one of them is five point 034 seconds. And the other one is that a common here? Minus, uh, 0.365 seconds. Well, we can't have minus time, so we're going to ignore that. We're going to use the positive time for our tea. So now, uh, we have X is equal to the of ex glossing extraction times T Okay, well, V of X is V not times that co sign Stada Times the time. Okay, well, for V, not you. Plug in 28 meters per second, multiply that by co sign of 61 degrees and then multiply that. By the time which we found to be 5.34 seconds, you'll find that the distance is 68 meters. So that's the solution to part a Okay, start a new page because for part B, it says, Well, the centerfielder starts at a position that was 105 meters away and sprints into where this ball is going to land and catches it right before he hits the ground. And they want you to know they want to know how fast he's going to be traveling in order to do that So his Velocity V would be equal to that distance that he's going to be covering divided by the time it would take him to cover it. Okay, that distance is the starting point 105 meters away, minus 68 because that's how far the ball goes so that the difference there is how far he needs to travel, divided by the time, which was 5.34 seconds. Okay, plug this into your calculator and this comes out to be a 7.3 meters per second. That's how fast the outfielder would need to run to get the ball

View More Answers From This Book

Find Another Textbook

03:16

block of mass m .00 kg is attached equilibrium and released from rest,sp…

02:17

A 3.5-cm radius hemisphere contains a total charge of 6.6 x1O-7= The flux th…

02:47

A hockey puck is launched horizontally from the top of a table Im off a floo…

03:14

A 2.0 cm x 3.0 cm rectangle lies in the xy-plane: What is the magnitude of t…

01:22

Problem #I:Calculate the thickness of shielding material needed to block…

01:25

A 50.0-g Super Ball traveling at 26.5 m/s bounces off a brick wall and rebou…

08:20

13 Using the average logarithmic energy decrement, estimate the number of co…

02:58

Five students are ask next question motion diagram for a baseball falling do…

02:11

Right-Hand Rule Magnelic ForcesAcellusL What direction does the magn…