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When you connect an unknown resistor across the t…

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81 Problem 82 Problem 83 Problem 84 Problem 85 Problem 86 Problem 87 Problem 88 Problem 89 Problem 90 Problem 91 Problem 92 Problem 93 Problem 94 Problem 95

Problem 19 Medium Difficulty

A battery-powered light bulb has a tungsten filament. When the switch connecting the bulb to the battery is first turned on and the temperature of the bulb is $20^{\circ} \mathrm{C},$ the current in the bulb is 0.860 A. After the bulb has been on for 30 s, the current is 0.220 A. What is then the temperature of the filament?

Answer

the temperature of the filament is $666.5^{\circ} \mathrm{C}$

Related Courses

Physics 102 Electricity and Magnetism

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Video Transcript

Current through the filament is 0.860 ampere at 20 degrees celsius after 30 seconds current through the filament is 0.220 ampere. Now we want to calculate a temperature at which current flowing through the filament is 0.20 ampere. So here we have current at 20 degree celsius is equal to 0.86 ampere. Here we have the reference temperature equal to 20 degrees celsius. Now, at latter temperature t we have an at that temperature equal to 0.220 ampere. Let v is the potential difference applied across the filament. Now the resistance of flament at 20 degree centigrade is equal to voltage applied across current flowing through the filament here. Voltage applied is v and gurn flowing through the filament is 0.60 ampere. So we have resistance equal to v upon 0.860 ampere. Now the resistance at t degrees celsius is equal to v upon current at 50 degree celsius that is equal to v. Upon current at d degree celsius is 0.220 ampere. Now we're using the relation that or a temperature t is equal to resistance at reference temperature into 1 plus temperature coefficient of resistance into temperature minus difference temperature. Now, why are putting different values here here? Residence at temperature t is v upon 0.220 ampere and resistance. At reference, temperature is v upon 0.60 ampere into 1 plus, and the value of alpha of dunstan flament is 0.0045 per degree centigrade into t. Minus 8 nat is 20 degree. Celcius from here, we can cancel b from both sides of the equation, so we have 0.860 ampere upon 0.220 ampere equal to 1 plus 0.0045 percent integratio t minus 20 degree celsius from here. We have 3.9090 equal to 1 plus 0.0045 per degree celsius into t minus 20 degree celsius. 93.9090. Minus 1 is equal to 0.0045 per degree celsius into t minus 20 degree celsius by subtracting the 2 terms. On the left hand, side of the equation we get 2.9090 is equal to 0.0045 per degree celsius into t minus 20 degree celsius. By dividing both sides by 0.0045 we get 2.9090 upon 0.0045 per degree. Celsius is equal to t minus 20 celcious from here we have t minus 20 degree. Celsius is equal to 646 degrees celsius or we have t equal to 646 degrees celsius plus 20 degrees celsius. So we have t equal to 6 s 6 degree. It'S the final answer:

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