Like

Report

A battery with an internal resistance of $10.0 \Omega$ produces an open circuit voltage of 12.0 $\mathrm{V}$ . A variable load resistance with a range from 0 to $30.0 \Omega$ is connected across the battery. (Note: A battery has a resistance that depends on the condition of its chemicals and that increases as the battery ages. This internal resistance can be represented in a simple circuit diagram as a resistor in series with the battery.) (a) Graph the power dissipated in the load resistor as a function of the load resistance. (b) With your graph, demonstrate the following important theorem: The power delivered to a load is a maximum if the load resistance equals the internal resistance of the source.

no answer available

You must be signed in to discuss.

University of Michigan - Ann Arbor

University of Washington

University of Sheffield

University of Winnipeg

in the first part of this question, we have two blood for the participation in terms of the Lord Resistance. So let me ride the formula for which we are going to plot the graph vehicles too Well, a fault. Old square. Are you worried by our minister? Old Square minus 40 Home. Here. This art is the Lord's resistance and teno is equal. End to that internal resistance more. The plot will be just like so. This is our block where we have beam waxes and external resistance had xxx So we see that you two goes on increasing when we are increasing their r and it becomes my trump too. R equals two minus 10. So the articles too, which is actually the internal resistance. And then it goes crazy s so we see that the peak is attended articles to 10. Well, which is the internal resistance. So it shows that this the serum which says that depart disposition, uh, his maximum had, uh to the point where external it's turned to become Sequels to the internal resistance is true.