00:01
You told you have a beam of light approaching a boundary between carbon disulfide and air.
00:06
The light is traveling in in this direction.
00:09
You're given this angle is 37 .5 degrees.
00:13
You're told the light is made up of three distinct colors.
00:15
Red, and red has an index of refraction that's given as 1 .61 .82.
00:28
Then you have yellow, which has an index of refraction, given as 1 .62.
00:37
And then finally blue and its index of refraction is given as n is 1 .6523.
00:49
Of course, in air, which is above the surface, we know that n is equal to one.
00:55
There's a detector over in this location and they want to know which of these three colors of white will make it through the detector implication being that at least one of these may reflect due to total internal reflection.
01:05
So what i would suggest is finding a critical angle for each one of these, you know that theta -critical is equal to sine inverse of the transmitted into material or n2 over what it's traveling in originally n1.
01:20
And so you can do that for each one of these.
01:22
So for red, theta -critical is equal to sign inverse of 1 over 1 .6182...