Question
A beam of monochromatic light experiences constructive interference when it shines on a soap film with a thickness of $183 \mathrm{~nm}$ and an index of refraction of $1.35$. What is the wavelength of the light?(Assume that $m=0$.)
Step 1
The formula for constructive interference is given by $2nt = m\lambda$, where $n$ is the index of refraction, $t$ is the thickness of the film, $m$ is the order of interference, and $\lambda$ is the wavelength of the light. Show more…
Show all steps
Your feedback will help us improve your experience
Prabhat Tyagi and 80 other educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Light with a wavelength of $615 \mathrm{~nm}$ experiences constructive interference when it shines on a soap film whose thickness is $117 \mathrm{~nm}$. What is the index of refraction of the soap film? (Assume that $m=0$.)
Calculate A beam of monochromatic light with a wavelength of $523 \mathrm{~nm}$ experiences destructive interference when it shines on a soap film with a thickness of $195 \mathrm{~nm}$. Assuming that $m=1$, what is the index of refraction of the soap film?
When monochromatic light shines perpendicularly on a soap film $(n=1.33)$ with air on each side, the second smallest nonzero film thickness for which destructive interference of reflected light is observed is 296 $\mathrm{nm}$ . What is the vacuum wavelength of the light in $\mathrm{nm}$ ?
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD