Question
A beam of unpolarized light in air is incident at an angle of $54.5^{\circ}$ (with respect to the normal) on a plane glass surface. The reflected beam is completely linearly polarized.(a) What is the refractive index of the glass? (b) What is the angle of refraction of the transmitted beam?
Step 1
Step 1: The Brewster's law states that the angle of incidence for which the reflected light is completely polarized is given by $\tan(\theta_B) = n$, where $n$ is the refractive index of the medium and $\theta_B$ is the Brewster's angle. Show more…
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$\bullet$$\bullet$ A beam of unpolarized light in air is incident at an angle of $54.5^{\circ}$ (with respect to the normal) on a plane glass surface. The reflected beam is completely linearly polarized. (a) What is the refractive index of the glass? (b) What is the angle of refraction of the transmitted beam?
A parallel beam of unpolarized light in air is incident at an angle of 54.5$^\circ$ (with respect to the normal) on a plane glass surface. The reflected beam is completely linearly polarized. (a) What is the refractive index of the glass? (b) What is the angle of refraction of the transmitted beam?
The Nature and Propagation of Light
Polarization
A parallel beam of unpolarized light in air is incident at an angle of $54.5^{\circ}$ (with respect to the normal) on a plane glass surface. The reflected beam is completely linearly polarized. (a) What is the refractive index of the glass? (b) What is the angle of refraction of the transmitted beam?
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