00:01
In this problem we have this incident light with intensity i0 and we want to compute what is intensity of the light at point a, b and t.
00:17
These points are separate by polarizers and the red lines represent the polarizing direction of the polarizers.
00:30
Well, in this kind of problems, we must distinguish two cases.
00:35
First, when the incident light is unpolarized, and second, when the incident light has a special polarizing direction.
00:49
In this problem, we are told that the incident light is unpolarized.
00:53
This is the simple of unpolarized light.
00:57
When this happened, only half of the incident light pass through the polarizer.
01:05
So the intensity of light at point a is just a zero over two.
01:13
In the direction of the electric field is the same as the direction of the polarizer.
01:21
So this is the direction of the electric field at point a.
01:26
This is vertical.
01:28
Well, now the light is not unpolarized anymore.
01:35
So we are in the second case.
01:38
When this happened and we want to compute what is the intensity of the light that pass through a polarizer, we need to compute what is the angle between the incident electric field and the polarizing direction of the polarizer.
01:56
In this case, this angle is the angle.
01:59
Is this, the angle is this, and we can see easily that this is 60 degrees, it's the same that this angle.
02:12
Well, now we can compute where is the intensity of the light at this point, and the intensity of the light is just the initial intensity of light times cosine square of the angle we have compute.
02:32
So, with this relation, we compute the intensity of the light that passed through a polarizer when the incident light has a special polarizing direction.
02:47
Well, this is just i0 over 2, and this is 1 half square...