Question
A bicyclist comes to a skidding stop in $10 \mathrm{~m}$. During this process, the force on the bicycle due to the road is $200 \mathrm{~N}$ and is directly opposed to the motion. The work done by the cycle on the road is$(\mathrm{A})+2000 \mathrm{~J}$(B) $-200 \mathrm{~J}$(C) Zero(D) $-20,000 \mathrm{~J}$
Step 1
Step 1: The work done by a force is given by the formula $W = F \cdot d \cdot \cos(\theta)$, where $F$ is the force, $d$ is the displacement, and $\theta$ is the angle between the force and the displacement. Show more…
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A bicyclist comes to a skidding stop in $10 \mathrm{~m}$. During this process, the force on the bicycle due to the road is $200 \mathrm{~N}$ and is directly opposed to the motion. The work done by the cycle on the road is $\quad$ [NCERT Exemplar] (a) $+2000 \mathrm{~J}$ (b) - $200 \mathrm{~J}$ (c) zero (d) $-20,000 \mathrm{~J}$
Work, Energy and Power
Round 1
A cyclist comes to a skidding stop in 10 m. During this process, the force on the cycle due to the road is 200 N and is directly opposed to the motion. (a) How much work does the road do on the cycle? (b) How much work does the cycle do on the road?
A bicyclist comes to a skidding stop in 10 m. During this process, the force on the bicycle due to the road is 200 N and is directly opposed to the motion. The work done by the cycle on the road is
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