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A billiard ball strikes and rebounds from the cushion of a pool table perpendicularly. The mass of the ball is $0.38 k g$. The ball approaches the cushion with a velocity of $+2.1 \mathrm{m} / \mathrm{s}$ and rebounds with a velocity of $-2.0 \mathrm{m} / \mathrm{s}$ . The ball remains in contact with the cushion for a time of $3.3 \times 10^{-3} \mathrm{s}$ What is the average net force (magnitude and direction) exerted on the ball by the cushion?

$-470 N$

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Numerade Educator

University of Washington

Simon Fraser University

University of Winnipeg

we begin this question by calculating what is the average acceleration off that boat? The acceleration is equals to the variation in the velocity divided by the time that it took. Then we had a velocity off 2.1, and now we have a velocity off. Mine is true, sir. The variation in the velocity is it goes to minus truth miners True 0.1 and the time it took waas 3.3 times. Stand to the minor street and these gives us minus four. Plunge divided by 3.3 times. Stand toe the minor street meters per second squared off acceleration now to countless the net force that had bean acting the live oak. During this time interval, we can use Newton's second law, which says the following the magnitude off the net force is equal to the mass off the ball times the acceleration. Then the magnitude off the net force is equals two 0.38 times, minus 4.1, divided by three What three times stand toe the minor street and these leaves as a net force. That is the question. Minors 4.1 times zero points, 38 divided by treatment three times. Stand to the third. We had 10 to the ministry down here. So now we have 10 to retort of here. We can do that. We can send this term up here, given that we worked the sign off the exponents and this gives us approximately minus 0.47 times 10 in return, which is equals two minus 470 noodles.

Brazilian Center for Research in Physics