00:01
We begin the first item of this question, noticing that the outer strip, which is formed by the red strip, measures r plus s times theta, while the inner strip composed by the blue strip measures r times theta.
00:21
Then we know that one r plus s times theta is equal to the expanded length.
00:31
Of the red strip, which is given by l plus l times alpha 2 times delta t.
00:38
And at the same time, you know that 2 r times theta is equal to l plus l times alpha 1 times delta t.
00:48
Now we have two equations.
00:51
We can eliminate theta by doing the following.
00:53
Pick equation 2 and solve it for theta.
00:56
So, theta is l plus l times alpha 1 times delta t.
01:01
Divided by r.
01:03
Then we can substitute theta in equation number one by this value of theta.
01:09
By doing that we get a new equation which tells us the following.
01:12
R plus s times theta which is l plus l times alpha 1 times delta t divided by r is equal to l plus l times alpha 2 times delta t.
01:31
Okay.
01:31
Now let me erase these two equations.
01:34
We will not need them anymore so that i can continue solving this problem.
01:39
Okay, now let me bring this equation here.
01:41
The first thing we should do is try to simplify this equation, and we can do that because we have a lot of factors of l.
01:48
So we can factor l here and we can factor l here.
01:52
By doing that, we get the following.
01:53
R plus s times l times 1 plus alpha 1 times delta t is equals to l times 1 plus alpha 2 times delta t and of course we have an r dividing the left hand side.
02:12
Now we can simplify l with l and this will make our life easier.
02:17
So now we have r plus s times 1 plus 1 plus alpha 1 times delta t equals to 1 plus alpha 2 times delta t and there is an r dividing the left -hand side.
02:35
Let me erase what i had just done so that i can have more space to continue solving this problem.
02:42
Okay now what can we do with this equation? we can solve it for r...