A black, totally absorbing piece of cardboard of area A=2.0 cm^2 intercepts light with an inten

step 1 So the radiation pressure piece of R would be equal to the intensity divided by the speed of lig

A black, totally absorbing piece of cardboard of area A=2.0...

A black, totally absorbing piece of cardboard of area $A=2.0 \mathrm{~cm}^{2}$ intercepts light with an intensity of $10 \mathrm{~W} / \mathrm{m}^{2}$ from a camera strobe light. What radiation pressure is produced on the cardboard by the light?

Key Concepts

Radiation Pressure

Radiation pressure refers to the force per unit area exerted on a surface by the momentum transfer of electromagnetic radiation (photons). It is a fundamental concept in understanding how light can exert mechanical pressure on objects through either absorption or reflection.

Intensity of Electromagnetic Radiation

Intensity, in the context of electromagnetic radiation, is the measure of power per unit area carried by a wave. It quantifies the amount of energy that passes through a given area per unit time, and directly influences the amount of radiation pressure when light interacts with a surface.

Momentum Transfer in Light-Matter Interaction

When photons impinge on a surface, they transfer momentum to it. The extent of this momentum transfer determines the force and, consequently, the radiation pressure on the surface. For a perfectly absorbing surface, the momentum transfer is directly proportional to the intensity of the incident light.

Relationship Between Intensity, Speed of Light, and Pressure

There is a direct relationship between the intensity of electromagnetic radiation and the radiation pressure it produces, given by the formula p = I/c for a totally absorbing surface. Here, I represents the intensity of the light, and c is the speed of light, linking the electromagnetic properties of light with the mechanical force exerted on materials.

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