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A block attached to an ideal spring undergoes simple harmonic motion. The acceleration of the block has its maximum magnitude at the point where(A) the speed is the maximum(B) the speed is the minimum(C) the restoring force is the minimum(D) the kinetic energy is the maximum

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Chapter 8

Oscillations

Oscillatory Motion

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the problem. We have given a block attached to an ideal spring, and it goes a simple harmonic motion. The exploration of the block has its maximum magnitude. So we know that acceleration is equal to minus omega square X. In simple harmonic motion, we had access the displacement. When access maximum, it is equal to amplitude. So the maximum value of exhalation is equal to omega is square a right. That means suppose this is a mean point. And this is that. And this is negatively. That means at this point, exhalation is maximum. Right? So we'll go out. Uh huh. All right. His speed is maximum. Speed is maximum. Yeah. Speed comics. Some of the main point. So you look at it. It's pretty as many of the speed as many. Right? That also there is tweeting forces. Many MKX. Yeah. Zero of that. Got to Lorraine. Mhm. Mm. Mhm. Google. It kind of energy is mixing up. Mhm. Yeah. Mhm. Okay, well, mhm. Help me. Look. Here's Andre. You

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