Question
A block is lying on the table. What is the angle between the action of the block on the table and the reaction of the table on the block?(a) $180^{\circ}$(b) $90^{\circ}$(c) $45^{\circ}$(d) $0^{\circ}$
Step 1
We need to find the angle between the action of the block on the table and the reaction of the table on the block. According to Newton's third law of motion, for every action, there is an equal and opposite reaction. Show more…
Show all steps
Your feedback will help us improve your experience
Dheeraj Sharma and 78 other educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A book is_lying on the table. What is the anglt between thenction of the book on the table and $t h$. reaction of the table on the book? (a) $0^{\circ}$ (b) $45^{\circ}$ (c) $90^{\circ}$ (d) $180^{\circ}$
A block of mass $m$ slides down on rough inclined plane of angle $\theta$ with the horizontal, with an acceleration a along the plane. The value of the reaction is (a) $\mathrm{m}(\mathrm{a}+\mathrm{g} \sin \theta)$ (b) $\mathrm{m} \cdot \frac{(\mathrm{a}+\mathrm{g} \sin \theta)}{\mathrm{g} \cos \theta} \cdot \mathrm{a}$ (c) $m g \cos \theta$ (d) $m \sqrt{g^{2}+a^{2}-2 a g \sin \theta}$
Assertion: A block is at rest on an inclined plane of inclination $\theta$, net contact force on the block is $m g$. Reason: If block is at rest, then net force on the block is zero. (A) A (B) $\mathrm{B}$ (C) $\mathrm{C}$ (D) D
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD