Question
A block of copper is heated from $20.0^{\circ} \mathrm{C}$ to $80.0^{\circ} \mathrm{C}$. How much heat is absorbed by the copper if its mass is $60.0 \mathrm{~g}$ ?
Step 1
We have the mass (m) of the copper block as $60.0 \, \text{g}$, and the change in temperature ($\Delta T$) is $80.0^{\circ} \mathrm{C} - 20.0^{\circ} \mathrm{C} = 60.0^{\circ} \mathrm{C}$. Show more…
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