00:01
In this question, it is given that there is a fresh water.
00:05
In the fresh water, there is some block of ice of area a and thickness 0 .5 meters on which one man is standing.
00:20
The moss of the man is given as 100 kg.
00:32
The thickness of the ice block is given as 0 .5 meters.
00:41
The specific gravity of the ice is given as 0 .917.
00:51
Specific gravity is nothing but the density of the particular substance, that is, the ice, divided by the density of water, that is the standard fluid.
01:04
Therefore, the density of ice is equal to 917 kilogram per cubic meter.
01:16
That is, the density of water is 1000 kg per cubic meter.
01:19
Multiply 1 ,000 with 0 .917, we obtained the density of ice as 917 kg per cubic meter.
01:33
Now, let us assume m might be the mass of the ice.
01:48
Now, for euclibrium, the summation of the weight of the man and the weight of the ice must be equal to the weight of the volume of water displaced.
02:00
Okay, the weight of the man and the weight of the ice can be written as m .i plus of the man...