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A block of ice with a mass of 2.50 $\mathrm{kg}$ is moving on a fric-tionless, horizontal surface. At $t=0,$ the block is moving tothe right with a velocity of magnitude 8.00 $\mathrm{m} / \mathrm{s}$ . Calculate themagnitude and direction of the velocity of the block after each of the following forces has been applied for 5.00 s: (a) a forceof 5.00 N directed to the right; (b) a force of 7.00 $\mathrm{N}$ directed tothe left.

a) 18 $\mathrm{m} / \mathrm{s}$b) 6 $\mathrm{m} / \mathrm{s}$

Physics 101 Mechanics

Chapter 8

Momentum

Physics Basics

Kinetic Energy

Potential Energy

Energy Conservation

Moment, Impulse, and Collisions

Atiya H.

March 1, 2021

It is struck by a 0.4 kg ball initially moving with a velocity of 0.25 m/s toward the right along the x-axis. After the collision, the 0.4 kg ball has a velocity of 0.2 m/s at an angle of 36.9° above the x-axis in the first quadrant. What is the magnitude

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in this problem, we have Ah, ice block off, master. 2.5 kilograms. Moving with velocity. Eight meters per second. The right word. Action. Not that this is a 0.0 meters. Corsican? No. For about a Want to see what happens if we apply a force off five mutants in the rightward direction or a time period off five seconds. Now, this is clearly an impulse problem. This is our force. Our forces five Newton on DH. That duration is five seconds on. The impulse generated by this force is forced times that Eurasian it was a plateful, which is five times five, which is 25 Katie meter for second. Now we know that impels is the same as change in momentum. That is final moment on minus initial momentum. Maybe impulse hens. The final moment off this block here will simply be the initial momentum. That's the impulse. This is the important takeaway from this problem. Once you know this, everything else becomes pretty clear Now we know that because we know the mass and the velocity off the object. Initially the initial known to me simply mass 2.4 kilograms times velocity eight it keeps us 20 Cajun meters per second. This is our initial moment and in this case, the first case. Our impulse is 25 18 meters per second and hence the final moment. It's 20 plus 25 the 20 from initial on 25 from the impulse 45. 18 meters per second. Now we know that momentum is simply mass times velocity where this velocity is the final velocity of the object. Hence our velocity is 45 divided by mass which is 215 kilograms which turns out to be 18 meters per second. No, you're supposed to write it down us 18.0 meter per second because all our numbers have three significant digits. Hence, this is the final velocity and note that this is positive, which means it is in the right direction. Now, for the second case, we are given off force in the left or direction with magnitude seven mutants. Hence we can ID. The force has minus seven mutants as usual, R X axis is in the right direction. In this case, the impulses force times the time period which is minus seven. The force times three times five which is minus 35 aged meter per second, hence using the same formula again. Our final momentum is initial moment of bliss impulse, which is initial moment. Of his 20 i know impulses minus 35. 18 meters per second. Giving us minus 15 is your meter per second. Now we know that momentum is mass times velocity again, which gives us velocity to be minus 15 by 2.5. She's minus six meters per second. As you can see, this velocity is negative, which means in this case, the object most in the left or direction with the magnitude six meters per second with speed of six meters per second Stegall.

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