A block of mass 2 kg is lying on a floor. The coefficient...

A block of mass $2 \mathrm{~kg}$ is lying on a floor. The coefficient of static friction is 0.54 . What will be the value of frictional force if the force is $2.8 \mathrm{~N}$ and $\mathrm{g}=10 \mathrm{~ms}^{-2}$
(a) zero
(b) $2 \mathrm{~N}$
(c) $2.8 \mathrm{~N}$
(d) $8 \mathrm{~N}$

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Key Concepts

Static Equilibrium

Static equilibrium occurs when all the forces acting on an object balance each other, resulting in no net motion. In the context of static friction, if the applied force is less than or equal to the maximum static frictional force, the frictional force will exactly balance the applied force to maintain equilibrium.

Normal Force

Normal force is the perpendicular contact force exerted by a surface on an object resting on it. In problems involving friction, it is used along with the coefficient of static friction to calculate the maximum possible static frictional force.

Static Friction

Static friction is the force that opposes the initiation of sliding motion between two surfaces in contact. It adapts to the magnitude of the applied force up to a maximum limit, ensuring that the object remains at rest as long as the applied force does not exceed this maximum.

Coefficient of Static Friction

The coefficient of static friction is a dimensionless quantity that represents the ratio between the maximum static frictional force and the normal force between two contacting surfaces. It serves as an indicator of how much frictional force is available before the object begins sliding.

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