A block of mass 250 g slides down an incline of inclination 37^∘ with a uniform speed. Find the

step 1 Okay, as per the question, a block of mass M equals to 250 gram slide down an incline of the inc

A block of mass 250 g slides down an incline of inclination...

A block of mass $250 \mathrm{~g}$ slides down an incline of inclination $37^{\circ}$ with a uniform speed. Find the work done against the friction as the block slides through $1 \cdot 0 \mathrm{~m}$.

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Key Concepts

Gravitational Force Decomposition

On an inclined plane, the weight of an object (mg) is resolved into two components: one perpendicular to the plane (mg·cos?) and one parallel to the plane (mg·sin?). The component parallel to the incline is responsible for causing the object to slide down.

Uniform Motion and Equilibrium

When an object slides at a constant speed, it is in dynamic equilibrium. This means that the net force acting along the direction of motion is zero. Consequently, the friction force exactly balances the component of gravitational force pulling the object down the incline.

Friction Force

Friction is the resistive force that opposes the relative motion between surfaces in contact. On an inclined plane, if the block moves at constant speed, the frictional force is equal in magnitude to the gravitational component parallel to the incline (mg·sin?), thereby preventing acceleration.

Work Done Against Friction

Work is defined as the product of the force component opposing the motion and the displacement in the direction of that force. In this context, the work done against friction during the motion is calculated by multiplying the magnitude of the friction force by the distance over which the block slides.

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