Question
A block of mass $5^{\circ} 0 \mathrm{~kg}$ slides down an incline of inclination $30^{\circ}$ and length $10 \mathrm{~m}$. Find the work done by the force of gravity.
Step 1
The force of gravity acting on the block is $mg$, where $g = 9.8 \, \text{m/s}^2$ is the acceleration due to gravity. However, the component of this force that acts along the incline is $mg \sin \theta$. Show more…
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"A block of mass 5.0 kg slides down an incline of inclination 30° and length 10 m. Find the work done by the force of gravity"
A 2.0-kilogram mass is pulled up a frictionless 30° incline at a constant speed of 0.5 meters per second. Determine the work done by force $F$ to move the mass to a vertical height of 2.0 meters. (A) 0 $\mathrm{J}$ (B) 5 $\mathrm{J}$ (C) 10 $\mathrm{J}$ (D) 20 $\mathrm{J}$ (E) 40 $\mathrm{J}$
Practice Test
Practice Test 1
A 3.00 -kg block slides down a frictionless plane inclined $20^{\circ}$ to the horizontal. If the length of the plane's surface is $1.50 \mathrm{~m}$, how much work is done, and by what force?
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