A block of mass m=0.1 kg is released from a height of 4 m on a curved smooth surface. On the h

step 1 In this question it is told that a block of mass 0 .1 KG is released from a height of 4 meter on

A block of mass m=0.1 kg is released from a height of 4 m...

A block of mass $m=0.1 \mathrm{~kg}$ is released from a height of $4 \mathrm{~m}$ on a curved smooth surface. On the horizontal smooth surface, it collides with a spring of force constant $800 \mathrm{~N} / \mathrm{m}$. The maximum compression in spring will be $\left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right)$ (A) $1 \mathrm{~cm}$ (B) $5 \mathrm{~cm}$ (C) $10 \mathrm{~cm}$ (D) $20 \mathrm{~cm}$

A block of mass $m=0.1 \mathrm{~kg}$ is released from a height of $4 \mathrm{~m}$ on a curved smooth surface. On the horizontal smooth surface, it collides with a spring of force constant $800 \mathrm{~N} / \mathrm{m}$. The maximum compression in spring will be $\left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right)$
(A) $1 \mathrm{~cm}$
(B) $5 \mathrm{~cm}$
(C) $10 \mathrm{~cm}$
(D) $20 \mathrm{~cm}$

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Elastic Potential Energy

This energy is stored in elastic objects such as springs when they are compressed or stretched. It is quantified by the formula (1/2)kx², where k is the spring constant and x is the displacement from equilibrium. This concept is crucial when analyzing systems involving springs, as it captures the energy stored and subsequently released by the spring.

Gravitational Potential Energy

This is the energy that an object possesses due to its position in a gravitational field and is given by the expression mgh, where m is mass, g is the acceleration due to gravity, and h is the height above a reference point. It is a key contributor to the energy calculations when objects are released from a height.

Conservation of Energy

This principle states that in an isolated system, the total energy remains constant even though it may be transformed from one form to another. In problems involving motion and forces without friction, it allows the transformation of gravitational potential energy into kinetic energy and then into other energy forms such as elastic potential energy, which can be used to solve for unknown quantities.

Transcript

Please give Ace some feedback