Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

A block of mass $m=2.20 \mathrm{kg}$ slides down a $30.0^{\circ}$ incline which is 3.60 $\mathrm{m}$ high. At the bottom, it strikes a block of mass $M=7.00 \mathrm{kg}$ which is at rest on a horizontal surface, Fig. 53 . (Assume a smooth transition at the bottom of the incline.) If the collision is elastic, and friction can be ignored, determine $(a)$ the speeds of the two blocks after the collision, and (b) how far back up the incline the smaller mass will go.

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

a) $-4.4 \mathrm{m} / \mathrm{s}$4.0 $\mathrm{m} / \mathrm{s}$b) 2.0 $\mathrm{m}$

Physics 101 Mechanics

Chapter 9

Linear Momentum

Motion Along a Straight Line

Kinetic Energy

Potential Energy

Energy Conservation

Moment, Impulse, and Collisions

Cornell University

University of Michigan - Ann Arbor

Simon Fraser University

Hope College

Lectures

04:05

In physics, a conservative force is a force that is path-independent, meaning that the total work done along any path in the field is the same. In other words, the work is independent of the path taken. The only force considered in classical physics to be conservative is gravitation.

03:47

In physics, the kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. The kinetic energy of a rotating object is the sum of the kinetic energies of the object's parts.

07:43

A block of mass $m=2.20 \m…

06:30

A block of mass $m = 2.50 …

04:36

A block of mass m=2.20m=2.…

02:39

A block of mass m = 3.00 k…

11:54

A $2.50-\mathrm{kg}$ block…

02:22

A block of mass $m$ starts…

05:39

A 1.00 -kg block initially…

14:59

04:07

A $3.00-\mathrm{kg}$ block…

08:18

An object of mass $10 \mat…

05:56

05:09

all right. Starting apart. A. The first step is defined velocity just before collision. So this would be from energy conservation. Initially, you have potential and gm to h times hide it. A is equal to mats 1/2 mass times velocity of a squared. So velocity that a is squared off to ju times headed A This is two times 9.8 meters per second squared times to be 0.6 meters. So this gives us 8.4 meters per second for velocity at a then we use Um then we use moment. Are the results for a classical the relationship between velocities for a, uh, elastic collision. And so a at minus B B initial velocities will be negative. A prime minus booby prime hole So and so Vehbi. As you know, zero for Avi be prime will be vey a plus b a prime. So this is 8.4 plus V a prime meters per second. And then finally we use energy conservation, our momentum conservation. I should say initially you have m times v a d A. Afterwards, you have m v a prime plus big m ah b uh, prime. And so this is M V a prime plus M times the A plus B b prime R v a prime mission. So replacing Vehbi prime here on DSO could take things common. You have m plus small m times be a prime physical to minus, uh, small and minus. I'm big, um, times v a So, therefore, create prime a small in minus began over big gamma plus small M times B A. This is 2.2 kilograms minus seven kilograms over 2.2 plus seven kilograms. Uh, times 8.4 meters per second. As you can see, the answer will be negative. It is, in fact, negative 4.4 meters per second. Uh, that's the A prime. Therefore, view be prime is a 0.4 minus 4.4 equals 4.0 meters per second in part beef. We're again using Momenta energy Conservation. So initially you have 1/2 m v a prime squared the kinetic energy, and that's converted potential energy. MGH prime, uh, and so h a prime. The height is equal to a V. A prime squared over to Judy. Uh, note that this is equal to D. A prime sign data and because this is because we want the distance long to incline, so they will be assigned data component to that. This is just vertical height there for D A promise what we want to do. A prime is equal to be a prime squared over to G side data. So this is, uh minus 4.4 meters per second, squared over two times 9.8 meters per second squared Todd Sign 30 giving us a distance of 1.96 meters.

View More Answers From This Book

Find Another Textbook

02:41

Suppose the coefficient of static friction between a quarter andthe back…

03:25

Answer the following to demonstrate your knowledge on Light andWave Natu…

02:06

A 418-Ω resistor, an uncharged 3.53-μF capacitor, and a 19.5-Vemf are co…

01:53

Calculate the attraction force between two apples placednext to each ot…

05:34

A student decides to move a box of books into her dormitory roomby pulli…

02:21

The front 1.20 m of a 1,600-kg car is designed as a "crumplezone&qu…