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A blue puck with mass 0.0400 $\mathrm{kg}$ , sliding with a velocity of magnitude 0.200 $\mathrm{m} / \mathrm{s}$ on a frictionless, horizontal air table, makes a perfectly elastic, head-on collision with a red puck with mass $m$ , initially at rest. After the collision, the velocity of the blue puck is 0.050 $\mathrm{m} / \mathrm{s}$ in the same direction as its initial velocity. Find (a) the velocity (magnitude and dircction) of the red puck after the collision; and (b) the mass $m$ of the red puck.

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(a) $v_{B 2}=0.250 \mathrm{m} / \mathrm{s}$ in the same direction of the blue puck(b) $m=0.0240 \mathrm{kg}$

Physics 101 Mechanics

Chapter 8

Momentum, Impulse, and Collisions

Moment, Impulse, and Collisions

University of Michigan - Ann Arbor

University of Washington

Hope College

Lectures

04:30

In classical mechanics, impulse is the integral of a force, F, over the time interval, t, for which it acts. In the case of a constant force, the resulting change in momentum is equal to the force itself, and the impulse is the change in momentum divided by the time during which the force acts. Impulse applied to an object produces an equivalent force to that of the object's mass multiplied by its velocity. In an inertial reference frame, an object that has no net force on it will continue at a constant velocity forever. In classical mechanics, the change in an object's motion, due to a force applied, is called its acceleration. The SI unit of measure for impulse is the newton second.

03:30

In physics, impulse is the integral of a force, F, over the time interval, t, for which it acts. Given a force, F, applied for a time, t, the resulting change in momentum, p, is equal to the impulse, I. Impulse applied to a mass, m, is also equal to the change in the object's kinetic energy, T, as a result of the force acting on it.

03:49

$\bullet$ A blue puck with…

05:17

A hockey puck with mass $0…

09:49

06:19

On a frictionless, horizon…

On a frictionless. horizun…

13:54

Hockey puck $B$ rests on a…

05:22

$\bullet$ On a frictionles…

09:53

13:22

A $0.300-\mathrm{kg}$ puck…

04:23

A 0.300 -kg puck, initiall…

Yeah, Here for the solution. Step and identify for elastic realism the moment Tom and energy are conserved for the next step. Setup. Giving data Mars off Blue pack It is M B called to 0.400 program. Initial velocity of blue pack VB one equal to 0.200 m per second initial velocity of red but we are one equal to zero. Final velocity of blue pack VB two equal to 0.50 m per second. Now execute for the party from the condition of plastic coalition When one body initially are addressed, we are tickled to be b one plus b b two. By substituting the value, we get 0.200 m per second plus 0.50 m per second. And from here we get We are to this zero point 250 m per second. Now for the part B now for the elastic collision with one body initial addressed from the velocity expression after the coalition, it is m r equal to Ambien bracket to vb one by. We are two minus one here By substituting the value we get 0.400 kg in bracket too. Multiply by 0.200 m per second, divided by zero my 00.250 m per second minus one. And by solving this week at 0.24 telegram. So this is the complete solution. Step by step. Please go through this. Thank you.

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