Question
A body dropped from a tower travels half of the total distance in the last second of its motion. The total time of fall will be $\left(\mathrm{g}=10 \mathrm{~m} \mathrm{~s}^{-2}\right)$(a) $\sqrt{2} \mathrm{~s}$(b) $2 \mathrm{~s}$(c) $2+\sqrt{2} \mathrm{~s}$(d) $2 \sqrt{2} \mathrm{~s}$
Step 1
According to the problem, the body covers half of the total distance in the last second of its motion. Therefore, the time taken to cover the first half of the distance is $T-1$. Show more…
Show all steps
Your feedback will help us improve your experience
Satpal Satpal and 56 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A body is dropped from the top of a tower of height $h$. It covers a distance $h / 3$ in the last sccond of its motion. If $g=10 \mathrm{~ms}^{-2}$, how much time docs it take to reach the ground? (a) $(21 \sqrt{3}) s$ (b) $\left(\begin{array}{ll}2 & \sqrt{3}) s\end{array}\right.$ (c) $(3 \mid \sqrt{6}) s$ (d) $(3 \sqrt{6}) s$
Motions in One Dimension
Section B
A body dropped from top of a tower fall through $40 \mathrm{~m}$ during the last two seconds of its fall. The height of tower is $\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right)$ (a) $60 \mathrm{~m}$ (b) $45 \mathrm{~m}$ (c) $80 \mathrm{~m}$ (d) $50 \mathrm{~m}$
KINEMATICS
Motion in a Straight Line
A body is thrown vertically upwards from the top $\mathrm{A}$ of a tower. It reaches the ground in $t$ second. If it is thrown vertically downwards from $A$ with the same speed it reaches the ground in $t_{2}$ second. If it is allowed to fall freely from $A$, then the time it takes to reach the ground is given by (a) $t=\frac{t_{1}+t_{2}}{2}$ (b) $t=\frac{t_{1}-t_{2}}{2}$ (c) $t=\sqrt{t_{1} t_{2}}$ (d) $\sqrt{\frac{t_{1}}{t_{2}}}$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD