Question
A body initially at $60^{\circ} \mathrm{C}$ cools to $50^{\circ} \mathrm{C}$ in 10 minutes. What will be its temperature at the end of next 10 minutes, if the room temperature is $25^{\circ} \mathrm{C}$. Assume Newton's law of cooling :(a) $42.85^{\circ} \mathrm{C}$(b) $45^{\circ} \mathrm{C}$(c) $40.46^{\circ} \mathrm{C}$(d) $44.23^{\circ} \mathrm{C}$
Step 1
Mathematically, it can be represented as: \[ \frac{dT}{dt} = -k(T - T_{0}) \] where \(T\) is the temperature of the body, \(T_{0}\) is the temperature of the surrounding, \(t\) is the time, and \(k\) is a constant. Show more…
Show all steps
Your feedback will help us improve your experience
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A body cools from $60^{\circ} \mathrm{C}$ to $50^{\circ} \mathrm{C}$ in $10 \mathrm{~min}$. If the room temperature is $25^{\circ} \mathrm{C}$ and assuming Newton's law of cooling to hold good, the temperature of the body at the end of the next 10 min will be (A) $38.5^{\circ} \mathrm{C}$ (B) $40^{\circ} \mathrm{C}$ (C) $42.85^{\circ} \mathrm{C}$ (D) $45^{\circ} \mathrm{C}$
A body cools in 5 minute from $60^{\circ} \mathrm{C}$ to $40^{\circ} \mathrm{C}$. The temperature of the surroundings is $10^{\circ} \mathrm{C}$. What is its temperature after the next 5 minute? (A) $32^{\circ} \mathrm{C}$ (B) $24^{\circ} \mathrm{C}$ (C) $28^{\circ} \mathrm{C}$ (D) $30^{\circ} \mathrm{C}$
A body takes $10 \mathrm{~min}$ to cool from $60^{\circ} \mathrm{C}$ to $50^{\circ} \mathrm{C}$. If the temperature of surrounding is $25^{\circ} \mathrm{C}$, then temperature of body after next 5 minutes will be: (a) $45^{\circ} \mathrm{C}$ (b) $42.85^{\circ} \mathrm{C}$ (c) $46.1^{\circ} \mathrm{C}$ (d) $47^{\circ} \mathrm{C}$
PROPERTIES OF BULK MATTER
Thermal Properties of Matter
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD