00:02
Since we're given acceleration, what we have to do is take the integral of this to get to velocity.
00:07
So that's kind of the work that's going on here.
00:12
And you add one to the exponent and divide by your new exponent.
00:15
Six divided by two gives me three.
00:17
And you have to consider some c value because the derivative of a constant is zero.
00:23
Well, we don't write that zero down.
00:25
So now what i need to consider is that they say the velocity is zero at t equals two.
00:30
So v of 2, i thought 2, i said 2, i wrote t is equal to 0.
00:38
So why is that important to consider? is that when i plug in 2 for this t, 2 squared as 4 times 3 is 12, plus that constant needs to equal 0.
00:49
And when you subtract 12 over, you get negative 12...