Question
A body of mass $0.5 \mathrm{~kg}$ is projected under gravity with a speed of $98 \mathrm{~m} / \mathrm{s}$ at an angle of $30^{\circ}$ with the horizontal. The change in momentum (in magnitude) of the body is(a) $24.5 \mathrm{~N}-\mathrm{s}$(b) $49.0 \mathrm{~N}-\mathrm{s}$(c) $98.0 \mathrm{~N}-\mathrm{s}$(d) $50.0 \mathrm{~N}-\mathrm{s}$
Step 1
The initial velocity can be broken down into horizontal and vertical components. The vertical component of the velocity is given by $u \sin(\theta)$, where $u$ is the initial speed and $\theta$ is the angle of projection. Show more…
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