Question
A body of mass $1 \mathrm{~kg}$ suspended from the free end of a spring having force constant $400 \mathrm{Nm}^{-1}$ is executing S.H.M. When the total energy of the system is 2 joule, the maximum acceleration is $\ldots \ldots . \mathrm{ms}^{-2}$.(A) $8 \mathrm{~ms}^{-2}$(B) $10 \mathrm{~ms}^{-2}$(C) $40 \mathrm{~ms}^{-2}$(D) $40 \mathrm{cms}^{-2}$
Step 1
Step 1: We are given that the mass of the body, $m = 1 \, \text{kg}$, the force constant of the spring, $k = 400 \, \text{Nm}^{-1}$, and the total energy of the system, $E = 2 \, \text{J}$. Show more…
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A mass $1 \mathrm{~kg}$ suspended from a spring whose force constant is $400 \mathrm{Nm}^{-1}$, executes simple harmonic oscillation. When the total energy of the oscillator is $2 \mathrm{~J}$, the maximum acceleration experienced by the mass will be (a) $2 \mathrm{~ms}^{-2}$ (b) $4 \mathrm{~ms}^{-2}$ (c) $40 \mathrm{~ms}^{-2}$ (d) $400 \mathrm{~ms}^{-2}$
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