Question
A body of mass $10 \mathrm{~kg}$ at rest is acted upon simultaneously by two forces $4 \mathrm{~N}$ and $3 \mathrm{~N}$ at right angles to each other. The $\mathrm{KE}$ at the end of 10 second is(a) $100 \mathrm{~J}$(b) $300 \mathrm{~J}$(c) $125 \mathrm{~J}$(d) $20 \mathrm{~J}$
Step 1
The net force acting on the body can be calculated using the Pythagorean theorem as these forces are at right angles to each other. The net force $F$ is given by \[F = \sqrt{4^2 + 3^2} = 5 \, \text{N}\] Show more…
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A body of mass 10kg at rest is acted upon simultaneously by two forces 4 N and 3N at right angles to each other. The kinetic energy of the body at the end of 10 sec is (a) 100 J (b) 300 J (c) 50 J (d) 125 J
A body of mass 10kg at rest is acted upon simultaneously by two forces 4 N and 3N at right angles to each other. The kinetic energy of the body at the end of 10 sec is
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