Question
A body starts with a certain initial velocity and moves with a constant deceleration along a straight line. If the distances travelled in the 5 th and 7 th second are in the ratio $\frac{31}{27}$, the body will come to a stop in time(a) $40 \mathrm{~s}$(b) $30 \mathrm{~s}$(c) $20 \mathrm{~s}$(d) $10 \mathrm{~s}$
Step 1
Step 1: We know that the distance travelled in the nth second can be represented as $u + \frac{1}{2}a(n-1)$, where $u$ is the initial velocity, $a$ is the acceleration (negative since it's deceleration), and $n$ is the time in seconds. Show more…
Show all steps
Your feedback will help us improve your experience
Satpal Satpal and 58 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A body starts with a certain initial velocity and moves with constant deceleration along a straight line. If distances travelled in the 5 th and 7 th second are in the ratio $\frac{31}{27}$, the distance travelled by the body before it stops is (a) $50 \mathrm{~m}$ (b) $100 \mathrm{~m}$ (c) $150 \mathrm{~m}$ (d) data insufficient
A body $A$ starts from rest with an acceleration $a_{1}$. After 2 seconds, another body $B$ starts from rest with an acceleration $a_{2}$. If they travel equal distances in the $5^{\text {th }}$ second, after the start of $A$, then the ratio $a_{1}: a_{2}$ is equal to (a) $5: 9$ (b) $5: 7$ (c) $9: 5$ (d) $9: 7$
A body A starts from rest with an acceleration 4. After 2 seconds, another body B starts from rest with an acceleration ay. If they travel equal distances in the 5th second, then the ratio a1 : a2 is equal to (a) 5:9 (c) 9:5 (b) 5:7 (d) 9:7
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD