00:01
Okay, so the first thing that we have to do is calculate the amount of energy released by 4 .2 grams of ethanol.
00:09
So we can do that by calculating the amount of energy needed to raise the temperature of the bomb calorimeter and water from 18 .5 degrees celsius to 22 .3 degrees celsius.
00:21
So the first thing that we can do is let's calculate delta t.
00:25
So delta t is equal to the temperature final minus the temperature initial.
00:31
So the temperature final is 22 .3 degrees celsius.
00:37
So let's convert that into kelvin's plus 273 minus 18 .5 degrees celsius plus 273.
00:44
That is also the conversion to kelvin, right? and we get duttsy to be equal to 3 .8 kelvin.
00:51
Now let's calculate how much energy is needed to raise the water from 18 .5 degrees celsius to 22 .3 degrees celsius.
00:59
So q is equal to m, so 650 grams.
01:04
C is 4 .182 joules per gram times kelvin.
01:08
That is the specific heat constant for water.
01:14
And delta t we calculated as 3 .8 kelvin.
01:17
Right.
01:18
Kelvin cancels, gram cancels, we're left for joules.
01:21
And we get q is equal to 103 to 9 .54.
01:28
Now let's calculate the amount of energy needed to raise the bottom colorimeter by 3 .8 degrees celsius.
01:35
So q is equal to c of bond which is 550 joules per kelvin and then we multiply that by the change in temperature which is 3 .8 kelvin right kelvin cancels or less of joules...