Question
A box of mass $8 \mathrm{~kg}$ is placed on a rough inclined plane of inclination $\theta$. Its downward motion can be prevented by applying an upward pull $F$ and it can be made to slide upwards by applying a force $2 F .$ The co-efficient of friction between the box and the inclined plane is(A) $\frac{1}{3} \tan \theta$(B) $3 \tan \theta$(C) $\frac{1}{2} \tan \theta$(D) $2 \tan \theta$
Step 1
This means that the applied force $F$ is equal to the weight component of the box along the inclined plane minus the frictional force. Mathematically, this can be written as: \[F = mg \sin \theta - \mu mg \cos \theta \tag{1}\] Show more…
Show all steps
Your feedback will help us improve your experience
Dheeraj Sharma and 79 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A box of mass $8 \mathrm{~kg}$ is placed on a rough inclined plane of inclination $\theta$. Its downward motion can be prevented by applying an upward pull $F$ and it can be made to slide upwards by applying a force $2 F$. The coefficient of friction between the box and the inclined plane is a. $(\tan \theta) / 3$ 1. $3 \tan \theta$ c. $(\tan \theta) / 2$ d. $2 \tan \theta$
A box of mass $8 \mathrm{~kg}$ is placed on a rough inclined plane of inclination $45^{\circ}$. Its downward motion can be prevented by applying an upward pull $F$ and it can be made to slide upwards by applying a force $2 F$. The coefficient of friction between the box and the inclined plane is a. $\frac{1}{2}$ b. $\frac{1}{\sqrt{2}}$ c. $\frac{1}{2 \sqrt{2}}$ d. $\frac{1}{3}$
A box of mass 8 kg is placed on a rough inclined plane of inclination q. Its downward motion can be prevented by applying an upward pull F and it can be made to slide upwards by applying a force 2F. The co-efficient of friction between the box and the inclined plane is
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD