a-box-with-a-mass-of-2-mathrmkg-accelerates-in-a-straight-line-from-4-mathrmm-mathrms-to-8-mathrmm-m

Question

A box with a mass of 2 $\mathrm{kg}$ accelerates in a straight line from 4 $\mathrm{m} / \mathrm{s}$ to 8 $\mathrm{m} / \mathrm{s}$ due to the application of a force whose duration is 0.5 $\mathrm{s}$ . Find the average strength of this force.
(A) 4 $\mathrm{N}$
(B) 8 $\mathrm{N}$
(C) 12 $\mathrm{N}$
(D) 16 $\mathrm{N}$

Khoobchandra Agrawal · Accepted Answer

Hi, everyone. Here it is. Given a box. Uh huh. Of mask two kg Accelerate from initial velocity of four m per second to final velocity of eight m per second in the time interval up 15 seconds. We have to calculate the average food supply Forces got the rate of change of momentum. Final momentum minus initial momentum upon time interval masses to eight minus four upon 40.5. So it is 1600. Mhm answered. It is correct.

Salamat Ali · Answer

There are two forces acting on the books. There is one is attention. And one is tiu the force of gravity. So the acceleration of the box, it will be mass times on 4 16 1 up box will create exploration, which is forces master. I&#x27;m exploration. That is attention minus off. Forced off gravity. Attention. We have his maximum 80 Newton minus. We have a box or four kg times. Um, 10 gravitational exploration. I want to find exploration than I will bring down a mass here. You just before. So 80 minus 40 40 divided by four. Used me. Uh, 10 meters per second squared. So this is my exploration off the box and option I have here is, um note. Aye. Ayes 2.5. He&#x27;s five. And C 7.5 d is 10. So option I have is, um d which is 10 s o d. End off the problem. Thank you for

Kathleen Tatem · Answer

Aloha. So for this problem, we are clones of Block that is caressing to forces at one and a two and moving in the ex direction told the Mass and by you off the giant it of F one. And it&#x27;s in the positive X direction. But we don&#x27;t know the value of F to That&#x27;s what we want to find and what we&#x27;re given for. Parts A through E is the value of the blocks acceleration. So you notice all this problem We use Newton&#x27;s second law, which is that the net force will equal to the mass times acceleration. The net force is the vector Some of these forces have long enough to So do you solve for F two, which is what we want to find. You can rearrange this equation. So the cap on May minus F one and this is really all happening in the ex direction so we can write this. Um, there&#x27;s m a X. That was a fun. It&#x27;s all in the extraction. So you did use the bank use of these forces. So then for part A, we&#x27;re told that exes 10 meters per second squared. So I have to be tika grams 10 meters per second squared minus 20 Nunes. And this of course kilograms times, meter per second stories and even says the 20 millions minus 20 Nunes or zero evens. So I have to zero in part A for part B, we have exes 20 meters per second squared. It&#x27;s actual be to kill grounds. Could be 40 Nunes minus 20 meetings. So that&#x27;s 20 new jeans, Um, as a vector. Also, the ex direction hurt, See x zero. So that means that we only have, um one term here Two is minus f lan which is minus 20. Mutants party The axes negative minus 10 meters per second squared. So have to be two kilograms times minus 10 years per second. Squared minus 29 years. So well, minus 20 minutes minus 20 evenings. So that&#x27;s minus 40. Newton&#x27;s work to you at the party X is minus 20 use for second squared. So just plugging in those numbers again, you should have minus 40. Nunes minus one is 20 times so minus 16 evens on the extraction

Jayashree Behera · Answer

salutes draw though forces acting on the optic. So we have eight. No dumb, it said. This is the object in then we have six ringtone on exacting conducted and there is a force f Which cord is the Mars on the object of the main interest now by Newton&#x27;s loving Know that Florida The loss for an object to stay addressed, the acceleration should be called a zero and hence the net force acting on the object must be equal to zero. And since over here the objectives are addressed in both directions. Therefore, we must have both these accelerations select Strada forces acting on the object. So we have eight. No, dumb, It said. This is the object in then we have six ringtone on sacked in a indulgent and there is a force f which gorges the Mars on the object of the main interest Stop a zero, which means that the neck forced in extra action will be zero and the neck force in my direction. Lots of equal zero selects it is off the force f into horizontal and vertical components, saying taking my ex to be to the right and lie to be a pro. And let&#x27;s see, this is the at this angle, Tita. So this will be my F X now by Newton&#x27;s love. We know that floors the laws for an object to stay addressed. The acceleration should be called a zero and hence the net force acting on the object must be equal to zero. And since over here the object is on addressed in both directions. Therefore, we must have both these accelerations, the horizontal component off If and this will be my vertical company off if and given this angle, Tita fix should be equal toe if course tita on dhe. If why should be going to have scientific up now? As I said, the net force should be equal to zero, which means that if X should be going to a Newton and f y, I should be going do six Newton our stop a zero, which means that the next forced in extra traction with a zero on the neck force in my direction, lots of equal zero. So let&#x27;s it is off the force f into horizontal and vertical components. So I&#x27;m taking my ex to be to the right and wanted to be a pro. And let&#x27;s see, this is the at this angle, Tita. So this will be my f X. The hole is under component off if and this will be my vertical company off if and given this angle, Tita affects should be equal to if course Tita on Dhe if why should be going to have scientific up now? As I said, the neck force should be equal to zero. Which means that if every these two expressions over here we get f course. Tita Toby eight knew them. And if scientific down to be eager to six names on now, in order to find the magnitude off s, I&#x27;m going to square these two equations and add them up. So I get f course to this Gradel&#x27;s. Of course, to top this squared off if scientists had to be equal to squared off eight Newton less scared off 16. So basically, I squared with the sides and added the corresponding sites off. Both take questions. So in the bracket, I have got squirted out the signs going Tick up on over here. I have 100 physical. I solved this So 100 Newtons crash Macosko teed up a science. Kartik basically is a cold one. It&#x27;s a techno metric law with subsidiaries to expressions. Over here we get f course teeter Toby eight knew them. And if scientists do the eager to six Newton now, in order to find the magnitude off S, I&#x27;m going to square these two equations and add them up. So I get f course Did this Gradel&#x27;s of course, to top this squared off if scientists had to be equal to squared off eight Newton less scared off 16. So basically I squared with the sides and added the corresponding sites off. Both take questions. So in the bracket, I have course qwerty So we get extract of the equal to 100 Newtons scratch, which means that f will be equal to load over off this and hence this vehicle to 10 new turn on him. Still correct. On such the equal will be option c. Thank you

Charles Carter · Answer

mimics example. 5.8. So we have two boxes, Uh, both of masses that we don&#x27;t notice. We&#x27;ll call him M one and M two You. We&#x27;re putting 30 Newtons of force, and the acceleration of toe in the X direction is 1.2 meters per second square. Okay. And the contact forces, 4.45 minutes. Find the massive box one in box two. Okay, so we know that the countless do box to first. So we know that the contact force, um, well, just do force contact equals m two times our acceleration in the X direction. So since we never contact forces 4.45 and we never exploration, extraction is 1.2. We just divide 4.45 but 1.2 3.71 kilograms. There&#x27;s our 1st 1 and then, ah, the total, uh, force in our total acceleration. Extraction can give us our some. So we have 30. Nunes equals M one plus 3.71 times 1.2. We have 30 equals 1.2 m one plus the 4.45 Okay, we subtract 4.45 from both sides. played 5.55 and that&#x27;s equal to 1.2 times are in one. So M one physical to 25.55 But about one point to you. But it is 21.29 kilograms. That&#x27;s clean, that a little bit can. And there&#x27;s the masses of our two blocks. Thank you very much.

Ryan Hood · Answer

in this problem. We have a box moving nine meters per second to the right, nine meters per second to the right and we want to know the distance traveled with for the speed is zero. We know that the force being employed on the object is equal to negative six t squared. And I say negative because I&#x27;m defying my positive X to be in this direction and so forces opposing the motion. So it&#x27;s in the negative direction Now. We can quickly figure out what the exhilaration with respect to time is by just using. Newton&#x27;s second Law is equal to the forced about it by the mess. And then we can plug in these two known. So they give us the mass and we do that. We get that acceleration is negative. Three t squared now confined v ft. From this by simply integrating this. And this is just a simple how role you&#x27;LL raise the exponents here two or three and then divide by three, which will cancel history. So when you integrate that, you get negative t cubed and then we have to add in our initial velocity which is non zero in this case initial velocity is nine expressing all units because they&#x27;re in the default units already. And so the ft is equal to negative t cute plus nine. So when V of tea is equal to zero, we can solve this for tea when V is equal to zero. This implies that take you to cycle to nine under solving this equation, setting v of t equals zero because we want all the time until it&#x27;s at rest. Now to sulfur to here we just take the cube root of nine. When we do that, we get that tea is you too. Two point zero seconds, and that&#x27;s the time it takes for the box. Do they come to rest and part being you want to actually, actually, is one more step in party. This is the time until it comes to rest. But we want to figure out the distance traveled during that time. And so there is one more step, and it&#x27;s that explain. Sex non is equal to one half being our plus p times t. This just killed Mac equation and we want to solve for electing inside, and we just solved for the time, which now allows us tow to put all the things in the right to solve For the left, our initial velocity was nine. Our final lawsuit zero in our time we just saw for was to point you away. And when we do this, we get nine point three six meters. That&#x27;s the actual final answer party now in part B. We want to figure out what the velocity is when the time is three seconds after the force being applied. And so for this we just pulling in V of three into form of the glossy that we found here. And so that&#x27;s the negative three. Cute, actually, Um, that&#x27;s not quite right. I need to put the negative outside. Thank you, root. Not that it really matters, but negative on the way and start three weeks Cube three. And then we take the negative ends up being the same thing, and we had nine. So I just pulling into you three and then whatever you do this out, you get negative eighteen meters per second, which means it&#x27;s moving to the left now at eighteen meters per second. And that&#x27;s the final answer for Barbie

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