00:01
On this problem, we're presented with a brass rod of a certain length and diameter.
00:07
It goes through a temperature change, and we're asked what forces needed to keep the bar contracting.
00:15
So this is a thermal stress problem, and our relevant equation is force over a cross -sectional area equals the opposite of young's modulus for whatever material times the coefficient of linear.
00:32
Expansion times change in temperature.
00:37
So let's make sure this is the equation for us.
00:41
We have force.
00:44
That's what we're looking for.
00:45
So it better be in the equation.
00:48
Cross -sectional area.
00:51
We're not given this, but we're given the diameter.
00:53
So we can easily find that.
00:57
Young's modulus.
00:59
That's based on the material.
01:01
We're told it's a brass rod.
01:03
So we can, or you can, look up the youngs modulus in a table in your physics textbook.
01:10
Same with the coefficient for linear expansion.
01:16
Change in temperature.
01:18
We don't have, but we do have the final and initial temperatures, so that's easy to find.
01:26
Okay, so let's start finding our values.
01:39
So for our area, it's circle.
01:44
So it's pi r, square...