00:01
So in this problem, we're told that a staircase has 30 steps, the bottom step has 100 bricks, and then each successive step is going to require two fewer bricks than the prior step.
00:12
So let's think of this like a sequence.
00:14
Well, that would mean that the first term would be 100, and if each term after the, or if each step after the first requires two less bricks, i simply keep subtracting two.
00:24
So the next step would have 98 bricks, and then 96, and then so forth, until we get to that.
00:30
30th term.
00:32
So part a in this question wants us to find how many bricks are required for the top step.
00:37
Well, we know that a sub 1 is equal to 100.
00:41
Because we're subtracting 2 to get from one term to the next, our common difference will be negative 2.
00:47
And we know that there's a total of 30 steps, so n will be equal to 30.
00:52
So we're going to use our formula to find the nth term in an arithmetic sequence, which is a sub n is equal to a sub 1 plus the quantity of n minus 1 times d.
01:02
So let's substitute in our values.
01:05
So we're going to have a sub 30 is equal to 100 plus the quantity of 30 minus 1 times negative 2.
01:14
Well, 30 minus 1 is 29 and 29 times negative 2 is negative 58...