00:01
Hi everyone, here it is given the hypothesis h .o2b, mean of muv, is called to mean of mua, and hypothesis 1 is mean of muv is less than mean of a for alpha to be.
00:33
0 .05, critical region given, n1 is called 2 3, and 2 is called 2 6 .6.
00:49
So u1 is less than or equal to two computation, original data and rank 1, 1, 7, 2 star, 8, 3 star, 9, 4, 10, 5 star, 11, 6, 12, 7, and 14, 7, and 14, 8, and 14, 9.
01:45
Now, w1 is equal to 10.
01:50
Hence, u1 you will get 10 minus 3 into 4 upon 2.
02:02
That is 4...