Question
A bullet hitting a wooden block loses half its velocity when it penetrates $60 \mathrm{~cm}$. If the retardation is uniform, it will come to rest after penetrating a further distance of(a) $10 \mathrm{~cm}$(b) $20 \mathrm{~cm}$(c) $30 \mathrm{~cm}$(d) $40 \mathrm{~cm}$
Step 1
We can use the equation of motion $v^2 = u^2 + 2as$ to express this, where $v$ is the final velocity, $u$ is the initial velocity, $a$ is the acceleration (in this case, retardation), and $s$ is the distance. Show more…
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A bullet fired into a large block of wood of uniform resistance, hits the block with a velocity of $48 \mathrm{~m} \mathrm{~s}^{-1}$. It penetrates a distance of $60 \mathrm{~cm}$ and the velocity is then reduced to $24 \mathrm{~m} \mathrm{~s}^{-1}$. It then penetrates a further distance of (in $\mathrm{cm}$ ) (a) 50 (b) 16 (c) 18 (d) 20
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