Question
A bullet in a gun is accelerated from the firing chamber to the end of the barrel at an average rate of $6.20 \times 10^{5} \mathrm{m} / \mathrm{s}^{2}$ for $8.10 \times 10^{-4}$ s. What is its muzzle velocity (that is, its final velocity)?
Step 1
The acceleration (a) is given as $6.20 \times 10^{5} \mathrm{m} / \mathrm{s}^{2}$ and the time (t) is given as $8.10 \times 10^{-4}$ s. The initial velocity (Vi) of the bullet is 0 since it starts from rest. Show more…
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A bullet in a gun is accelerated from the firing chamber to the end of the barrel at an average rate of $6.20 \times 10^{5} \mathrm{m} / \mathrm{s}^{2}$ for $8.10 \times 10^{-4} \mathrm{s}$. What is its muzzle velocity (that is, its final velocity)?
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