Question
A bullet of mass $40 \mathrm{~g}$ travels at $1000 \mathrm{~m} / \mathrm{sec}$. (a) What wavelength can we associate with it? (b) Why does the wave nature of the bullet not reveal itself through diffraction effects?
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The equation is given as: \[ \lambda = \frac{h}{mv} \] Show more…
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A bullet of mass 40 g travels at 1000 $\mathrm{m} / \mathrm{s} .$ Although the bullet is clearly too large to be treated as a matter wave, determine what Eq. $38-17$ predicts for the de Broglie wavelength of the bullet at that speed.
A bullet leaves the barrel of a rifle with a speed of $300.0 \mathrm{m} / \mathrm{s} .$ The mass of the bullet is $10.0 \mathrm{g} .$ (a) What is the de Broglie wavelength of the bullet? (b) Compare $\lambda$ with the diameter of a proton (about $1 \mathrm{fm}$ ). (c) Is it possible to observe wave properties of the bullet, such as diffraction? Explain.
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