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A bus makes a trip according to the position-time graph shown in the drawing. What is the average velocity (magnitude and direction) of the bus during each of the segments $A, B,$ and $C$ ? Express your answers in $\mathrm{km} / \mathrm{h}$ .

$-2.0 \times 10^{1} k m / h$$-1.0 \times 10^{1} k m / h$40$k m / h$

Physics 101 Mechanics

Chapter 2

Kinematics in One Dimension

Motion Along a Straight Line

Alyssa J.

October 2, 2021

Part B is +10 km/h

University of Michigan - Ann Arbor

University of Washington

McMaster University

Lectures

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this problem is asking us to find the velocity, um, of a bus during its trip based on a position versus time graph. Now the key thing here is that velocity from a position versus time graph is equal to the slope slope of the position versus time graph. So that means for all three sections A, B and C. We're just looking at the slope of the line now. One thing to note here is that that means right away you can tell if these air going to be positives or negatives, because if the line is going downwards, it's a negative slope. So negative velocity. If the line is going upwards, it's a positive slope, so a positive velocity. So my final answers for all of these, if we're looking just at the sign, is a will be a negative velocity. But BNC will both be positives. Now. My rise overrun for all these forgetting the slopes just means we need to find a part of the graph where you can easily measure a change in velocity and a change in time. Um, if we look at the first graph, the first one second sees a change of velocity of 20 meters, so that one is going to be our rise of negative 20 over our run of one second. So we get a velocity of negative 20 meters per second for looking at B. It takes one second for it to go from 10 to 20. So it has a positive change of 10 in one second. So it's traveling at 10 meters per second and for part C, we don't have a nice one. Second interval. We can look at here. The closest we can get is 2/2 of a second and in half a second that see actually goes up by 20. So 20 divided by 0.5 gives us a positive 40 meters per second for our velocity.

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