Question
a. Calculate and display the molecular orbitals of $\mathrm{BF}_{3}, \mathrm{NH}_{3},$ and the $\mathrm{F}_{3} \mathrm{B}-\mathrm{NH}_{3}$ Lewis acid-base adduct.b. Examine the bonding and antibonding orbitals involved in the $\mathrm{B}-\mathrm{N}$ bond in $\mathrm{F}_{3} \mathrm{B}-\mathrm{NH}_{3}$. Is the bonding orbital polarized toward the $\mathrm{B}$ or the $\mathrm{N}$ ? The antibonding orbital? Explain briefly.
Step 1
In $\mathrm{BF}_{3}$ and $\mathrm{NH}_{3}$, $\mathrm{NH}_{3}$ has a lone pair of electrons that can be donated, making it the Lewis base. On the other hand, $\mathrm{BF}_{3}$ has an empty orbital, making it the Lewis acid. Show more…
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