00:01
Okay, so we're given this reaction.
00:02
We're given this piece of information right here.
00:05
And we are asked to a first calculate the gipsree energy of the reaction.
00:11
So let's go ahead and write down our tl plus pb2 plus yields.
00:24
And let's put our pbs right here and our thallium plus.
00:30
Whoops see.
00:34
And that'll be to two and a two.
00:44
Okay.
00:45
So now to get our delta g, this one is zero.
00:53
This one, whoopsie.
00:54
Yep, that one's zero, that one's zero.
00:56
Lead is negative 24 .39.
01:01
And this is negative 32 .4.
01:05
And that'll be kilojoules per mole and kilojoules per mole.
01:11
So my delta g for the reaction will be equal to my coefficient 2 moles times negative 32 .4 kilojoules per mole minus 1 mole times negative 24 .39 kilojoules per mole.
01:40
And this will equal negative 40 .1 kilojoules.
01:58
So there's my answer for the first part.
02:02
And then for b, we're asked to do what? from delta g, find standard cell potential for, i keep writing an h there.
02:37
Okay...