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(a) Calculate the energy released by the destruction of 1.00 $\mathrm{kg}$ of mass. (b) How many kilograms could be lifted to a 10.0 $\mathrm{km}$ height by this amount of energy?
(a) $E=9.00 \times 10^{16} \mathrm{J}$(b) $m=9.18 \times 10^{11} \mathrm{kg}$
Physics 103
Chapter 28
Special Relativity
Relativity
Rutgers, The State University of New Jersey
Simon Fraser University
McMaster University
Lectures
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as we know it. The rest moss energy is given by E is equal to M C Square. Here is the muscle bill object M is the mass of the object. Marce the object and C is the speed of light, and C is equal to 3.0 Multiply by 10 to the power it made her for a second. Well, the most of the material M is equal to one kilogram. Most of the material is one kilogram. Well, let's say easy go to M. C. Square is secret number one. Well, the rest most energy off the one kilogram mass can be found by using equity number one, so the rest mass energy off one kilogram mass is equal to 1.0 kilogram. Multiply by C is 3.0 Multiply by 10 to the power eight meter or second old square, and therefore he is a cool too 9.0 multiplied by down to the power 16 kilogram made her square per second squared and therefore e is a cool too nine point 00 multiplied by 10 to the power 16. Jules. All right, Well, at least was far too you Now let's so part B. Well, we know that potential energy equals M g h Hear Etch is a cool too 10 kilometers, 10 10 kilometers and it's equal to 10 points. It'll multiply by 10 per tip over tree meters and, uh, it is given that the energy, calculated in part A it's stored in the material is ah to the potential energy and therefore potential energy equation can be returnees be divided by G H and B potential energy is mind boring. 00 Multiply by 10 to the power 16. Jules, divided by G, is 9.8 meter per second square. Multiply by height. This is, ah, hide edge and it is a 10. Multiply by 10 to the power free meters and simply find this. We get a 9.18 line point warm eight. Multiply by 10 to the power 11 kilogram
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