00:02
Alright, so in this problem, we have a charge at the origin.
00:09
So this is xy, and the charge is q equal negative 8 nano columns.
00:19
So for part a, we want to...
00:26
So at this position, you can actually just check out the exercise 21 to 7.
00:33
And you can see that the electric field at that point p is negative 11 .11 .11 .m.
00:43
Plus 14 j.
00:45
Newton per columns.
00:47
And for part a, we want to find out the magnitude and direction of this electrofield.
00:53
So the magnitude is easy to simply 11 squared plus 14 squared and square root.
00:59
So the value is 17 .8 newton per columns.
01:02
And the direction is just utilized arc tangent 14 over negative 11...