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Hi.
00:02
In the given problem, this is the uniform electric field in the horizontal direction.
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And in this field, a dipole has been kept.
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Suppose this is minus q charge and this is here plus q charge.
00:27
The length of the dipole is given as d.
00:31
These charges, the dipole charges, are having a magnitude plus minus q is equal to plus minus 3 .0 microculum.
00:46
The dipole length d is given as 7 .0 centimeter and this uniform electric field e is having a magnitude of 2 .0 into 10 ratio power 4 newton per coulum.
01:02
Now in the first part of the problem we have to find net force acting on this dipole.
01:08
So here this negative charge will experience an electrostatic force in a direction opposite to the electric field whose magnitude is q into e and this positive charge will experience the same electrostatic force q into e but in the direction of electric field because we know electric field moves from positive to negative so this negative charge will experience a force towards the positive and this positive charge will experience the same force towards the negative.
01:38
Hence the net force experienced by the dipole is let it be f.
01:52
So this will be qe minus qe because the two forces are equal in magnitude and opposite in direction.
02:00
So the net force experienced by the dipole is zero.
02:04
The answer for the first part of the problem...