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a) Calculate the number of grams of deuterium in an $80,000$ -L swimming pool, given deuterium is 0.0150$\%$ of natural hydrogen. (b) Find the energy released in joules if this deuterium isfused via the reaction $^{2} \mathrm{H}+^{2} \mathrm{H} \rightarrow^{3} \mathrm{He}+n$(c) Could the neutrons be used to create more energy?(d) Discuss the amount of this type of energy in a swimming pool as compared to that in, say, a gallon of gasoline, also taking into consideration that water is far more abundant.

a. 2664 $\mathrm{g}$b. $2.09 \times 10^{14} \mathrm{J}$c. $n+^{1} \mathrm{H} \rightarrow^{2} \mathrm{H}+\gamma$d. Energy is 6 times order bigger than that of gasoline

Physics 103

Chapter 32

Medical Applications of Nuclear Physics

Nuclear Physics

Simon Fraser University

University of Sheffield

McMaster University

Lectures

02:51

In physics, wave optics is…

10:02

Interference is a phenomen…

07:16

Approximately $1$ of every…

04:43

Approximately 1 of every 3…

02:38

Roughly 0.0150$\%$ of the …

08:23

World energy consumption i…

05:44

A water sample is found to…

10:48

Of all the hydrogen in the…

03:44

$\bullet$ In a hypothetica…

08:31

05:33

The fusion reaction $\frac…

03:11

(a) Estimate the years tha…

07:24

Of all the hydrogen nuclei…

04:45

The oceans have a volume o…

02:12

How many kilograms of wate…

01:30

Hydrogen is found in two n…

05:00

How much heavy water (deut…

00:55

02:26

Deuterium, $^{2} \mathrm{H…

06:16

It has been proposed that …

02:28

There is approximately $10…

09:11

You're enthusiastic a…

now problem Assertive three in chapter study to impart, Avery needs to calculate the weight with deuterium in assuming poor to tear were made about a zero point all pitching perf end of natural hydra. So 1st 11 you to calculate the number off water number or water in this well import, so is eight times 10 to the force leaders water. And we know that the intensity the maxims that your water is one kilo mc one kilogram per liter. So So the weight in this women poor is about 80 times 10 to the fourth kilograms on. We know that the Moola math or water is smaller. Math is 18 grams poem boil. So first of all, we calculate the number or boils. All this water is eight times 10 to the force kilograms over 18 grams. Palm oil on this gives us four corner for four times 10 to the four miles. So we know that the chemical chemical presentation or what I used to as 20 so in one water in one water, Morley killed there would be two hydrogen. So the number oh hydrogen Sandro hydrogen is actually two times this number two times system. So it's eight times eight eight times 10 to the six Moyle. So the number off due to rim is that we write it as to the number off. Due to room is this number we label it to be. The star is Starr times zero point all 15% and this gives us 1332 miles. So the math we know that is the mullah. Math or hydrogen to is about tool. Grandma's palm oil. So 1332 miles once the rescue it true Moyle times to Grandma's palm oil E Coast to 66 for greatness. This is a weight in this women poor overto to Roman. Next in part of B be Well, he said that the dew tour, um, is is fused. Has a reaction. Oh, too. Do a two room is formed. Thio he there, Ms Dewey class unusual. So first living in to calculate the energy release off this reaction. So for one reaction, the math loss is to em too. Minus minus. The Stewie miners the math off mutual minus and minus Emlyn sometimes a C squared and this gives us Ah number was 3.27 mega electoral. What's so This is this is energy released in one reaction. So we need to know how much reaction there is in this We impart. So every reaction consumes too due to room. So we have we have. We have calculated that in previous ah previous problem, there is 13 is through a tomb oils. So the number over action is this number divided by two times avocados numbers. This is the number of reaction. So the energy loss told her energy laws will be this number of times the energy loss. In one reaction, the result is 1.31 times turned to the 20 seven's mega electro poles and the he asked us a tow calculated the energy released in jewels and become one of these two dross. This e coz 2.0 ni kind stand to the 14 clothes. How do we characterize this is actually with we multiplies this number in multiple eyes this number by 1.6 times 10 to the minors. So tins Okay, so next next, a product, he asks if this neutron can be used, the two to create a more energy. Actually, we have seen that in problem of 27 you know, in problems 32 there are reactions Yours neutral like one neutron plus one hydrogen one. You get hydrogen to go to room, plus a mammary. And we also have one neutron. Ah, reactive is helium sui. We get hearing more form on the gamma route so this neutral actually can be reused to produce more energy And the four part of D it asks if ah to compare the energy release in the swim Emperor as that Oh, a gallon or gasoline from table. So important one. We know that for a gallon or gasoline the generous 1.2 times 10 toe the ace duo so energy. This is for a gallon of gasoline. So we compared the energy was the energy off? Was the energy released in this women? Power is this number is actually about a six times other bigger six times or they're bigger. So actually, this if we can use this energy

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