00:01
This question wants us to calculate the ph of a buffer that has 0 .12 molar lactic acid and 0 .11 molar sodium lactate.
00:28
Okay, so we know that ph is equal to p -k -a plus log of the conjugate base over the conjugate acid.
00:42
So, ha in this case is the lactic acid and a minus is sodium lactic.
00:51
Alright? so if we assume that the pkk is 3 .8, so then ph will be equal to 3 .8 plus log of 0 .11 over 0 .12.
01:11
So ph then will be equal to 3 .822.
01:27
So this is the first part.
01:34
The second part told us that it's 5 mil of 0 .13 molar lactic acid was mixed with 95 mil of 0 .15 molar sodium lactic.
01:57
So we have to find the ph after this happened.
02:05
So the total volume will be equal to 85 plus 95 mil, and that's 180 mil.
02:23
Then number of mol of lactic acid will be equal to, we have 0 .13 molar, and the volume is 85 mil, so, you just, so that's going to be 0 .085...