00:01
For this question, we want to calculate the rate of heat conduction between house walls that we are told have a thermal conductivity twice that of glass wool.
00:14
So the equation we want to use for this problem is heat transfer, q over time, equals k, which is the thermal conductivity of the material times the area, times the change in temperature, divided by the thickness d.
00:35
So in this case, we are told that k is twice that of glass wool, which if you look up is 0 .042 joules per second times meter times degrees celsius.
01:00
So that's just 0 .084 joules.
01:06
Smc.
01:08
Area from the problem statement is 120 square meters.
01:14
The temperatures are, we're going to use 18.
01:20
These are the inside and outside parts of the wall, 18 degrees celsius and 5 degrees celsius.
01:27
And then the thickness d is given as 13 centimeters...