Question
(a) Calcule el incremento de energía más pequeño (un cuanto) que puede ser emitido o absorbido a una longitud de onda de $812 \mathrm{~nm}$. (b) Calcule la energia de un fotón con frecuencia de $2.72 \times 10^{13} \mathrm{~s}^{-1}$. (c) Determine la longitud de onda de la radiación cuyos fotones tienen una energía de $7.84 \times 10^{-18} \mathrm{~J}$. ¿En qué porción del espectro electromagnético se encontraría esta radiación?
Step 1
626 \times 10^{-34} \mathrm{~J\cdot s}$), $c$ es la velocidad de la luz ($3.00 \times 10^8 \mathrm{~m/s}$), y $\lambda$ es la longitud de onda. Show more…
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(a) Calculate the energy of a photon of electromagnetic radiation whose frequency is $2.94 \times 10^{14} \mathrm{s}^{-1} .$ (b) Calculate the energy of a photon of radiation whose wavelength is 413 nm. (c) What wavelength of radiation has photons of energy $6.06 \times 10^{-19} \mathrm{J} ?$
Part A) Calculate the energy of a photon of electromagnetic radiation whose frequency is 2.76×10^14 s^-1. Express your answer to three significant figures and include the appropriate units. Part B) Calculate the energy of a photon of radiation whose wavelength is 410 nm. Express your answer to three significant figures and include the appropriate units. Part C) Calculate the wavelength of radiation of photons with energy E = 6.26×10^-19 J. Express your answer to three significant figures and include the appropriate units.
5 (a) Calculate the energy of a photon of electromagnetic radiation whose frequency is 2.94 * 1014 s - 1. (b) Calculate the energy of a photon of radiation whose wavelength is 413 nm. (c) What wavelength of radiation has photons of energy 6.06 * 10 - 19 J
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