00:01
So in this problem, we actually have a camera initially set up for f number equals 4.
00:07
And the exposure time of the camera is 1 over 15 seconds.
00:12
Now, we want to take a picture of a fast moving object.
00:16
And then for that case, we actually want to decrease the exposure time.
00:21
So what we do is we change it to 1 over 125 seconds.
00:27
So now for that case, we want to find out the f number, the final f number, all right? so let's begin.
00:34
The first thing that we need to know here is initially it was set up at correct exposure, and we want to change the f number in such a way that we are still getting the correct exposure.
00:47
So what does that mean physically? so what that means is in both of the cases, initial and final cases, the energy that is being delivered to the film of the camera, is the same, all right? sufficient energy so that you get the correct exposure.
01:06
So let's begin with that.
01:07
So the energy, let's say e1 is the initial energy, has to be equal to e2, both of the energies that are being delivered to the film.
01:20
All right? so now from the definition of the intensity, intensity i is actually the energy per unit area, per unit time.
01:34
All right.
01:35
So from here we can actually rearrange and write for the equation here for this e1 equals e2.
01:42
We can write this down.
01:44
This is going to be i1 times a times t1 equals i2 times a times t2...